Every time the roller spins one revolution, the conveyor is moved a linear distance equivalent to the circumference of the roller. "WE SERVICE WHAT WE SELL" + 0 lbs. = 30.5 lbs. We use cookies to personalize content and analyze traffic. per foot (including chain @ 2.5 lbs. There are few, if any, short cuts in the process of determining the chain pull on an endless chain conveyor. However, by knowing the value of the various factors, the total chain pull may be determined by the point to point accumulation method of calculation. Multiply weight of the chain (3.0 lbs.) Count how many full rotations are made by the roller in one minute. When the head and tail pulley are the same size:L=(D+d)/2 x 3.1416+2CWhen one pulley is larger than the other pulley:L=(D+d)/2 x 3.1416+2C+(D-d)2/4c, At one time when the load is known per square foot:P= G1 x C(in feet)x W (in feet)At one time when load is known by pounds per hour:P=G2/(S x 60) x C(in feet), Level Conveyors:HP=(F x S x (P+M))/33,000Inclined Conveyors:HP=((P x B)+(P+M)x F x S)/33,000, Pull needed to move belt and load horizontally:E= F x (P+M), Total tension to move belt and load horizontally:E2= E+E1, Additional tension required to prevent slippage on drive pulley:E1=Ex K, Determines the working strength of the belt to handle the job on per inch of width basis:T= E2/W. Jesse Randall studied mathematics and physics and works as an embedded electronics engineer, developing microcontroller firmware and digital interfaces. by the number of feet of chain. In systems having multiple rises and falls, this may be treated somewhat differently, depending on loading patterns. + (6'-0 x 30 lbs./ft.) chain pull. It should be noted that these percentages are for average conveyors that travel under normal conditions. In the following computation, it will be seen that the footage from the down stream end of the drive to the far tangent of the next curve (0 to 1) is multiplied by .45 lbs. Trigonometry can provide the sine of any angle, but the following angles of slope are most used. + 2% =, 4 Introduction of inclines and declines in a system further complicates chain pull calculation by adding to the forces. Online Store Terms and Warranty. hooks and 6 lb. E. Total of A, B, C, D = total live load on the conveyor system. We are a non-profit group that run this service to share documents. =, 1 Objects and materials placed on top of the conveyor belt will be moved from one edge to the other as the rollers spin. When making measurements, keep fingers away from the rollers. + 218.69 + 2% =, 6 to 1 = 6.7 ft. x .4575 lbs./ft. STEP #2: DETERMINE QUANTITY OF LOADED AND UNLOADED CARRIERS. and the 2% friction for the 90 curve is added. + 2% =, 4 Many factors, which vary greatly from system to system, influence the end result. In situations where the loads are more than 2'-0" on centers, a more accurate result can be achieved by multiplying the total live load on the inclined portion by the sine of the angle of incline. B. Due to the elevations changes, the formula for finding the pounds per foot chain pull is arranged differently because it must be assumed that at some point the incline will be loaded and the decline empty. Please help us to share our service with your friends. Zojo Site by ZojoMedia.com. Calculate the distance traveled for one hour. To determine the chain pull due to friction, multiply total moving load by selected friction factor. to 6 = 8.1 ft. x .4575 lbs./ft. Design Data - Step 4: Chain Pull Calculation. to 3 = 8.1 ft. x .4575 lbs./ft. A. The lift load for the elevation changes of the conveyor is equal to the total lift height (in feet) multiplied by the individual product weight (in pounds), then divided by the load spacing centers in feet. Multiply the diameter of the roller by pi, 3.14159. This calculation yields the circumference of the rollers. + 3.13 lbs. per foot) x 100'-0" or 1000 lbs. or 180 lbs. He has been writing on technology-related subjects since 2000. loads on 1'-0" centers would be 10 lbs. Manufacturers and grocery stores typically use conveyors to move products along a specific path. It is expressed as (6-0 x 30 lbs./ft.) Pi is a dimensionless factor, meaning it does not matter whether inches, centimeters or any other units of measurement are used. + 197.06 lbs. @ 1.50% = 15 lbs. Distance traveled (displacement) per a change in time is the definition of velocity (speed and direction). 542.17 If calculated chain pull using this short cut method is in excess of 550 pounds per drive, you must use the long point-to-point accumulation method of calculation. + 2% =, 1 Next, the footage from (1) to (2) is multiplied by .45 lbs., added to the 3.08 lb. per foot x 1.50% = .4575 lbs./ft. as the additional force induced by the rise. x 0.707107= 383.37 lbs. The following formula provides a result of .45 pounds per foot. Chain Pull, SHORT CUT METHOD OF CHAIN PULL CALCULATION (Approximation Only). They can pull your fingers in quickly and smash them between the conveyor belt, causing severe injury. =. Multiply one more time by 60 to arrive at the total inches traveled per hour which equals 3,768. chain pull. C. Multiply weight of empty product hooks or carriers by total number of carriers in system. =, CHAIN PULL CALCULATION FOR A MULTI-LEVEL SYSTEM. To arrive at this figure, it is necessary to add the lift load and the friction factors, expressed as a small percentage of the live load, which act as resistance to the progress of the conveyor. March 23, 2018 | Author: Madison Lindsey | Category: N/A, Report "Chain Conveyors Practical Calculations", Share & Embed "Chain Conveyors Practical Calculations". + 226.84 lbs. Thank you for using our services. In Figure #2, a conveyor is shown identical to Figure #1 except for the addition of an incline and decline. Next, divide by 12, then divide by 5,280, to convert to miles per hour (12 inches = 1 foot and 5,280 feet = 1 mile). We need your help to maintenance and improve this website. Multiply weight of pendants by required number of total pendants in system. Add lift load obtained in Step #4 to (A) to obtain total chain pull. to 0 = 33.8 ft. x .4575 lbs./ft. Get product updates and company news delivered directly to your inbox. The net vertical rise (in feet) will be considered the total lifting height of the conveyor. To convert the speed of the conveyor belt from inches per minute to miles per hour, multiply by 60 to convert to inches per hour. Understanding a basic conveyor belt calculation will ensure your conveyor design is accurate and is not putting too many demands on your system. - (6'-0 x 30 lbs./ft.) In Figure #1 a simple system about 115'-0" long is shown with four horizontal curves. + 2% =, 5 The required number of carriers is equal to the total conveyor length divided by the carrier spacing. This calculation provides the linear distance traversed by a point on the conveyor belt in one minute. To calculate this force, determine the difference in elevation of all the vertical curves traveling upward in the system. When the loads are spaced under 2'-0" on centers, the formula of the total pounds per foot multiplied by the rise in feet can be used to determine the additional force in pounds for the inclined section. to 0 = 42.4 ft. x .4575 lbs./ft. Measure the circumference of the rollers in the conveyor , calculate revolutions per minute and then multiply these two figures together to determine conveyor belt speed. resultant plus 2% for the 90 curve. You consent to our cookies if you continue to use this website. + 2% =, 2 The speed at which the conveyor belt moves depends on the size of the rollers and their revolutions per minute. When adverse environment conditions exist or the conveyor is abnormally long or complex and exceeds the chain pull capacity of one drive, a progressive chain pull computation is necessary where the friction losses are progressively calculated and accumulated through the path along the conveyor. + 3.13 lbs. Multiply the RPM by the circumference of the roller. + 2%, 3 + 31.89 lbs. About Us | Products | Services | Resources | Contact Us | Site Map CHAIN PULL CALCULATION FOR A LEVEL SYSTEM. Please fill this form, we will try to respond as soon as possible. Chain pull is the effort necessary to maintain the normal operating speed of a conveyor under a related load. 0 to 5 = 37.9 ft. x .4575 lbs./ft. 0 A large number of vertical and horizontal curves will create slightly higher friction. The above friction factors were obtained from accurate laboratory tests with lubricated chain and have been verified by dynamometer tests of complete systems. Copyright 2017 McGinty Conveyors Inc. All rights reserved. It will be seen that a maximum of four loads can be on the incline at any one time. Friction resistance is found in the bearings of the chain wheels, curves, and the drive unit itself. + 2% =, 2 Divide this distance by carrier spacing to determine number of loaded carriers. + 6.97 lbs. Using a 2.50% friction factor for the short cut method will cover most normal conditions. For example, a roller with a diameter of 2 inches, has a circumference of 2 x 3.14159 or 6.28 inches. to 4 = 13.6 ft. x .4575 lbs./ft. + 2% =, 3 Measure the revolutions per minute of the rollers. D. Multiply weight of product only by number of loaded carriers only as determined in Step #2. Establish distance from loading to unloading. Next, divide by 12 to arrive at 314 feet, then divide by 5,280, to convert to miles per hour, 12 inches = 1 foot and 5,280 feet = 1 mile. For instance, a 100'-0" conveyor with 1.5 lb. Measure the diameter of the rollers around which the conveyor belt is wrapped. to 2 = 8.1 ft. x 4575 lbs./ft. Multiply total live load from (E) in Step #3 by friction factor of .025. Please copy and paste this embed script to where you want to embed. + 6.97 lbs. The lift load is the amount of force required to pull the live load upward along the vertical curves in the entire system. Speak With A Sparks Representative For Help With Your Conveyor Belt Calculations. To keep our site running, we need your help to cover our server cost (about $500/m), a small donation will help us a lot. Product carrier weight, product weight, coefficient of friction, track curves, inclines, declines, temperature and lubrication are some of the principle items affecting chain pull. lbs. 2022 Leaf Group Ltd. / Leaf Group Media, All Rights Reserved. + 36.31 lbs. The procedure of accumulating at each curve is followed back to "0". Multiply that figure by the number of revolutions, in this example, 10 to arrive at a total of 62.8 inches traveled per minute. He writes about subjects including abiogenesis, electrochemistry and algorithm optimization. We also share information about your use of our site with our social media, advertising, and analytics partners who may combine it with other information that you've provided or that we have collected from your use of our services. This can be seen in the chain pull calculation for the conveyor in Figure #2 from point #3 to #4. A. Our goal is to make science relevant and fun for everyone. to 1 = 11 ft. x .4575 lbs./ft. The live load on a conveyor is equal to the sum of weights of the chain, pendants, product hook or carrier, and the product. Distance traveled, or displacement, per a change in time is the definition of velocity, or speed and direction. It will be seen that straight conveyor has a friction factor of 1.50%. However, an endless conveyor chain must at least have horizontal curves, and each of these generate additional forces which must be taken into account as will be seen in Figure #1. Whether you need help solving quadratic equations, inspiration for the upcoming science fair or the latest update on a major storm, Sciencing is here to help. Copyright 2022 Sparks Belting All Rights Reserved | Privacy Policy | Business Terms, inclined belt conveyor design calculation. B. Therefore, if a conveyor did not have any vertical or horizontal curves, inclines or declines, the weight of the total live or moving load could be multiplied by 1.50% to determine the weight in pounds to move the conveyor. The first item to be determined is the pounds in chain pull per foot of straight conveyor. to 2 = 6.7 ft. x .4575 lbs./ft. In this example, the conveyor runs at approximately 0.05947 MPH. to 3 = 53.1 ft. x .4575 lbs./ft. to 4 = 8.1 ft. x .4575 lbs./ft.